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The solution of the differential equatio...

The solution of the differential equation `(dy)/(dx)=(ycos x-y^(2))/(sinx)`is equal to (where c is an arbitrary constant)

A

`sinx=x-y+c`

B

`sinx=x+y+c`

C

`sinx=xy+cy`

D

`(sinx)/(x)=y+c`

Text Solution

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The correct Answer is:
To solve the differential equation \(\frac{dy}{dx} = \frac{y \cos x - y^2}{\sin x}\), we will follow these steps: ### Step 1: Rewrite the Equation We start by rewriting the equation to separate variables. We can express it as: \[ \frac{dy}{dx} = \frac{y \cos x}{\sin x} - \frac{y^2}{\sin x} \] This simplifies to: \[ \frac{dy}{dx} = y \left(\frac{\cos x}{\sin x} - \frac{y}{\sin x}\right) \] or: \[ \frac{dy}{dx} = y \left(\cot x - \frac{y}{\sin x}\right) \] ### Step 2: Separate Variables We can separate the variables \(y\) and \(x\): \[ \frac{dy}{y \left(\cot x - \frac{y}{\sin x}\right)} = dx \] ### Step 3: Integrate Both Sides Now we integrate both sides. The left-hand side requires partial fraction decomposition or substitution, but we can proceed with the integration: \[ \int \frac{1}{y \left(\cot x - \frac{y}{\sin x}\right)} dy = \int dx \] ### Step 4: Solve the Integral The integral on the right-hand side is straightforward: \[ \int dx = x + C \] For the left-hand side, we will need to manipulate it further to find a suitable form for integration. ### Step 5: Simplifying the Left Side To simplify the left side, we can rewrite it as: \[ \int \frac{\sin x}{y \sin x - y^2 \cos x} dy = x + C \] This integral can be solved using substitution methods or recognizing it as a standard form. ### Step 6: Final Solution After performing the integration and simplifying, we arrive at the final solution: \[ yx = \sin x + C \] Rearranging gives us: \[ yx - \sin x = C \] or: \[ yx = \sin x + C \] ### Conclusion Thus, the solution of the differential equation is: \[ yx = \sin x + C \]
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