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29.2% (w//w) HCl stock, solution has a d...

`29.2% (w//w) HCl` stock, solution has a density of `1.25 g mL^(-1)`. The molecular weight of `HCl` is `36.5 g mol^(-1)`. The volume `(mL)` of stock solution required to prepare a `200 mL` solution of `0.4 M HCl` is :

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29.2% (w/w) HCl stock solution has a density of 1.25 g mL^(-1) . The molecular weight of HCl is 36.5 g "mol"^(-1) . The volume (mL) of stock solution required to prepare a 200mL solution of 0.4 M HCl is :

29.2% (w/w) HCl stock solution has a density of 1.25 g mL^(-1) . The molecular weight of HCl is 36.5 g "mol"^(-1) . Find the Volume (V)(mL) of stock solution required to prepare a 500 mL solution of 0.4 M HCl. Report your answer as V//5

29.2% (W//W) HCl stock solution has density of 1.25g mL^(-1) . The molar mass of HCl is 36.5g mol^(-1) . The volume (mL) of stock solution required to prepare a 200 mL solution of 0.4M HCl is

29.2 % (W//W) HCl stock solution has a density of 1.25 "g mL"^(-1) . The molecular mass of HCl is 36.5 g mol^(1) . What is the volume (mL) of stock required to prepare 200 mL of solution of 0.4 M HCl ?

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