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The pH of 0.1 M solution of the followin...

The pH of 0.1 M solution of the following salts increases in the order

A

`NaCl lt NH_(4)Cl lt NaCN lt HCl`

B

`HCl lt NH_(4)Cl lt NaCl lt NaCN`

C

`NaCN lt NH_(4)Cl lt NaCl lt HCl`

D

`HCl lt NaCl lt NaCN lt NH_(4)Cl`

Text Solution

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The correct Answer is:
To determine the increasing order of pH for a 0.1 M solution of the given salts (NaCl, HCl, NH4Cl, and NaCN), we need to analyze the nature of each salt and how they affect the pH of the solution. ### Step-by-Step Solution: 1. **Identify the Nature of Each Salt:** - **NaCl:** This salt is formed from a strong acid (HCl) and a strong base (NaOH). Therefore, it is neutral and will have a pH of 7. - **HCl:** This is a strong acid. A 0.1 M solution of HCl will have a pH less than 7. Specifically, since it completely dissociates, the pH can be calculated as: \[ \text{pH} = -\log[H^+] = -\log[0.1] = 1 \] - **NH4Cl:** This salt is formed from a weak base (NH4OH) and a strong acid (HCl). The pH will be less than 7 but greater than that of HCl because NH4Cl will produce NH4+ ions, which can slightly increase the acidity. The pH will typically be around 5-6. - **NaCN:** This salt is formed from a strong base (NaOH) and a weak acid (HCN). The pH will be greater than 7 because NaCN will produce CN- ions, which will make the solution basic. The pH can be calculated to be around 10-11. 2. **Compare the pH Values:** - HCl: pH ≈ 1 (lowest) - NH4Cl: pH ≈ 5-6 - NaCl: pH = 7 (neutral) - NaCN: pH ≈ 10-11 (highest) 3. **Determine the Increasing Order of pH:** - From the above analysis, we can arrange the salts in order of increasing pH: - HCl < NH4Cl < NaCl < NaCN ### Final Answer: The increasing order of pH for the 0.1 M solutions of the given salts is: **HCl < NH4Cl < NaCl < NaCN**
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