Which of the following are not more basic than `Al(OH)_(3)`?

Options

A. `Ca(OH_(2), Ce(OH)_(3)`
B. `Yb(OH)_(3), Lu(OH)_(3)`
C. `B(OH)_(3), Be(OH)_(2)`
D. `Ce(OH), Lu(OH)_(3)`

Answer

To determine which of the given compounds are not more basic than \( \text{Al(OH)}_3 \), we need to analyze the basicity of each compound in relation to aluminum hydroxide.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We need to compare \( \text{Al(OH)}_3 \) with other hydroxides mentioned in the question. The common candidates are likely to include hydroxides of alkaline earth metals and lanthanides.

2. **Understand Basicity**:
Basicity refers to the ability of a substance to accept protons (H⁺ ions) or donate hydroxide ions (OH⁻). Generally, as we move down a group in the periodic table, the basicity of hydroxides increases due to increased metallic character.

3. **Analyze \( \text{Al(OH)}_3 \)**:
Aluminum hydroxide is amphoteric, meaning it can act as both an acid and a base. However, it is generally considered to have moderate basicity compared to other hydroxides.

4. **Compare with Alkaline Earth Metals**:
Compounds like \( \text{Ca(OH)}_2 \) (calcium hydroxide) are more basic than \( \text{Al(OH)}_3 \) because calcium is in the alkaline earth metal group, and its hydroxide is more soluble and has a higher tendency to donate OH⁻ ions.

5. **Compare with Lanthanides**:
Lanthanide hydroxides, such as \( \text{Ce(OH)}_3 \) (cerium hydroxide), \( \text{Lu(OH)}_3 \) (lutetium hydroxide), and \( \text{Yb(OH)}_3 \) (ytterbium hydroxide), are also more basic than \( \text{Al(OH)}_3 \) due to their increased metallic character as we move down the lanthanide series.

6. **Consider Beryllium and Boron Hydroxides**:
Beryllium hydroxide \( \text{Be(OH)}_2 \) and boron hydroxide \( \text{B(OH)}_3 \) are less basic than \( \text{Al(OH)}_3 \). Beryllium has a high lattice energy and is less soluble, while boron is a metalloid with lower basicity.

7. **Conclusion**:
The compounds that are not more basic than \( \text{Al(OH)}_3 \) are \( \text{Be(OH)}_2 \) and \( \text{B(OH)}_3 \).

### Final Answer:
The compounds that are not more basic than \( \text{Al(OH)}_3 \) are:
- \( \text{Be(OH)}_2 \)
- \( \text{B(OH)}_3 \)