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Three numbers a, b and c are in between ...

Three numbers a, b and c are in between 2 and 18 such that 2, a, b are in A.P. and b, c, 18 are in G.P . If `a+b+c=25`, then the value of `c-a` is

A

4

B

3

C

7

D

0

Text Solution

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The correct Answer is:
To solve the problem, we need to find the values of \( a \), \( b \), and \( c \) given the conditions of the problem. Let's break it down step by step. ### Step 1: Understand the conditions We know that: 1. \( 2, a, b \) are in Arithmetic Progression (A.P.) 2. \( b, c, 18 \) are in Geometric Progression (G.P.) 3. \( a + b + c = 25 \) ### Step 2: Express \( a \) in terms of \( b \) Since \( 2, a, b \) are in A.P., we can write: \[ a = \frac{2 + b}{2} \] ### Step 3: Express \( c \) in terms of \( b \) Since \( b, c, 18 \) are in G.P., we can write: \[ c = \sqrt{b \cdot 18} = 3\sqrt{2b} \] ### Step 4: Substitute \( a \) and \( c \) into the equation \( a + b + c = 25 \) Substituting the expressions for \( a \) and \( c \): \[ \frac{2 + b}{2} + b + 3\sqrt{2b} = 25 \] ### Step 5: Clear the fraction by multiplying through by 2 Multiplying the entire equation by 2 to eliminate the fraction: \[ 2 + b + 2b + 6\sqrt{2b} = 50 \] This simplifies to: \[ 3b + 6\sqrt{2b} = 48 \] ### Step 6: Rearrange the equation Rearranging gives: \[ 3b + 6\sqrt{2b} - 48 = 0 \] ### Step 7: Isolate the square root term We can isolate the square root term: \[ 6\sqrt{2b} = 48 - 3b \] ### Step 8: Square both sides to eliminate the square root Squaring both sides: \[ 36 \cdot 2b = (48 - 3b)^2 \] This expands to: \[ 72b = 2304 - 288b + 9b^2 \] ### Step 9: Rearrange into a standard quadratic equation Rearranging gives: \[ 9b^2 - 360b + 2304 = 0 \] ### Step 10: Solve the quadratic equation using the quadratic formula Using the quadratic formula \( b = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A} \): Here, \( A = 9 \), \( B = -360 \), and \( C = 2304 \). Calculating the discriminant: \[ B^2 - 4AC = (-360)^2 - 4 \cdot 9 \cdot 2304 = 129600 - 82944 = 46656 \] Now, calculating \( b \): \[ b = \frac{360 \pm \sqrt{46656}}{18} \] Calculating \( \sqrt{46656} = 216 \): \[ b = \frac{360 \pm 216}{18} \] This gives us two possible values for \( b \): 1. \( b = \frac{576}{18} = 32 \) (not valid since \( b \) must be between 2 and 18) 2. \( b = \frac{144}{18} = 8 \) ### Step 11: Find \( a \) and \( c \) Now substituting \( b = 8 \) back into the equations for \( a \) and \( c \): \[ a = \frac{2 + 8}{2} = 5 \] \[ c = 3\sqrt{2 \cdot 8} = 3\sqrt{16} = 12 \] ### Step 12: Calculate \( c - a \) Finally, we find: \[ c - a = 12 - 5 = 7 \] ### Final Answer The value of \( c - a \) is \( \boxed{7} \).
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