On heating a mixture of `NaCl, K_(2)Cr_(2)O_(7)` and conc. `H_(2)SO_(4)` which of the following is formed ?

Options

A. `CrO_(2)Cl`
B. `CrO_(2)Cl_(2)`
C. `CrOCl_(2)`
D. `NaClO_(2)`

Answer

To solve the question of what is formed when heating a mixture of NaCl, K2Cr2O7, and concentrated H2SO4, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in the mixture are:
- Sodium Chloride (NaCl)
- Potassium Dichromate (K2Cr2O7)
- Concentrated Sulfuric Acid (H2SO4)

### Step 2: Understand the Reaction
When K2Cr2O7 is heated with concentrated H2SO4 and NaCl, a specific reaction occurs. Potassium dichromate reacts with sodium chloride in the presence of sulfuric acid to produce chromyl chloride (CrO2Cl2), potassium sulfate (K2SO4), sodium sulfate (Na2SO4), and water (H2O).

### Step 3: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction can be written as follows:

\[ K_2Cr_2O_7 + 4NaCl + 3H_2SO_4 \rightarrow 2CrO_2Cl_2 + K_2SO_4 + 2Na_2SO_4 + 3H_2O \]

### Step 4: Identify the Products
From the balanced equation, we can identify the products formed:
- Chromyl Chloride (CrO2Cl2)
- Potassium Sulfate (K2SO4)
- Sodium Sulfate (Na2SO4)
- Water (H2O)

### Conclusion
The main product of the reaction when heating NaCl, K2Cr2O7, and concentrated H2SO4 is **Chromyl Chloride (CrO2Cl2)**, which is known for its red fumes.

---