In the Freundich adsorption isotherm, the value of `((1)/(n))` is between 0 and ………… .

Answer

To solve the question regarding the value of \(\frac{1}{n}\) in the Freundlich adsorption isotherm, we need to understand the context of the isotherm and its mathematical representation.

### Step-by-Step Solution:

1. **Understanding Freundlich Adsorption Isotherm**:
The Freundlich adsorption isotherm describes how the amount of adsorbate (gas or liquid) adsorbed onto a solid surface varies with pressure at a constant temperature. The mathematical expression is given as:
\[ \frac{x}{m} = k \cdot p^{\frac{1}{n}} \]
where:
- \(x\) = mass of adsorbate
- \(m\) = mass of adsorbent
- \(k\) = Freundlich constant
- \(p\) = pressure of the adsorbate

2. **Identifying the Range of \(\frac{1}{n}\)**:
In the expression, \(\frac{1}{n}\) is an exponent that influences how the amount of adsorbate varies with pressure. The value of \(\frac{1}{n}\) is crucial in determining the nature of adsorption:
- If \(\frac{1}{n} = 1\), the relationship is linear.
- If \(\frac{1}{n} < 1\), the adsorption increases more rapidly with pressure.
- If \(\frac{1}{n} > 1\), the adsorption increases less rapidly with pressure.

3. **Determining the Limits**:
- The value of \(\frac{1}{n}\) can theoretically range from 0 to 1.
- When \(\frac{1}{n} = 0\), it implies that the adsorption does not depend on pressure (constant adsorption).
- When \(\frac{1}{n} = 1\), it indicates a direct proportionality between the amount adsorbed and pressure.

4. **Conclusion**:
Therefore, the value of \(\frac{1}{n}\) in the Freundlich adsorption isotherm is between 0 and 1.

### Final Answer:
The value of \(\frac{1}{n}\) is between 0 and 1.