An equilateral triangle ABC is cut from a thin solid sheet of wood .(see figure ) D,E and F are the mid-points of its sides as shown and G is the centre of the triangle.The moment of inertia of the triangle about an axis passing through G and perpendicular to the plane to the triangle is `I_(0)` If the smaller triangle DEF is removed from ABC , the moment of inertia of the remaining figure about the same axis is I. Then :

Options

A. `I=(3)/(4)I_(0)`
B. `I=(15)/(16)I_(0)`
C. `I=(9)/(16)I+(0)`
D. `I=(I_(0))/(4)`

Answer

B