The incorrect statement about the oxoacids, `HClO_(4)` and `HClO`, is

Options

A. The central atom in both `HClO_(4)` and `HClO` is `sp^(3)` hybridized
B. `HClO_(4)` is formed in the reaction between `Cl_(2)` and `H_(2)O`
C. The conjugate base of `HClO_(4)` weaker base than `H_(2)O`
D. `HClO_(4)` is more acidic than `HClO` because of the resonance stabilization of its anion

Answer

To determine the incorrect statement about the oxoacids \( HClO_4 \) and \( HClO \), we will analyze each statement provided in the context of the properties and structures of these acids.

### Step-by-Step Solution:

1. **Understanding the Hybridization of the Central Atom:**
- For \( HClO_4 \):
- The structure consists of one chlorine atom (Cl) bonded to four oxygen atoms (O), one of which is connected through a hydroxyl group (OH).
- The chlorine atom in \( HClO_4 \) is surrounded by four bond pairs (one single bond to OH and three double bonds to O), and it has no lone pairs.
- Therefore, the hybridization of Cl in \( HClO_4 \) is \( sp^3 \).

- For \( HClO \):
- The structure consists of one chlorine atom bonded to one oxygen atom and one hydrogen atom.
- The chlorine atom in \( HClO \) has one bond pair (to O) and three lone pairs.
- Therefore, the hybridization of Cl in \( HClO \) is also \( sp^3 \).

**Conclusion:** The statement that the central atom in both \( HClO_4 \) and \( HClO \) is \( sp^3 \)-hybridized is **correct**.

2. **Formation of \( HClO_4 \) from \( Cl_2 \) and \( H_2O \):**
- The reaction between \( Cl_2 \) and \( H_2O \) typically produces \( HCl \) and \( HOCl \) (hypochlorous acid).
- \( HClO_4 \) is not formed in this reaction.

**Conclusion:** The statement that \( HClO_4 \) is formed in the reaction between \( Cl_2 \) and \( H_2O \) is **incorrect**.

3. **Conjugate Base Strength of \( HClO_4 \):**
- The conjugate base of \( HClO_4 \) is \( ClO_4^- \).
- Since \( HClO_4 \) is a strong acid, its conjugate base \( ClO_4^- \) is weak.
- Water is a weak acid, and its conjugate base \( OH^- \) is strong.

**Conclusion:** The statement that the conjugate base of \( HClO_4 \) is weaker than water is **correct**.

4. **Acidity Comparison of \( HClO_4 \) and \( HClO \):**
- \( HClO_4 \) is a stronger acid than \( HClO \) due to the resonance stabilization of its conjugate base \( ClO_4^- \).
- In contrast, the conjugate base \( ClO^- \) of \( HClO \) does not have resonance stabilization.

**Conclusion:** The statement that \( HClO_4 \) is more acidic than \( HClO \) because of resonance stabilization is **correct**.

### Final Answer:
The incorrect statement about the oxoacids \( HClO_4 \) and \( HClO \) is that **\( HClO_4 \) is formed in the reaction between \( Cl_2 \) and \( H_2O \)**.