2 - Methylpent -2- ene on reductive ozonlysis will give

Options

A. Propanal only
B. Proapnal and ethanal
C. Propanone & propanal
D. Propan -2- ol and ethanal

Answer

To solve the problem of what products are obtained from the reductive ozonolysis of 2-methylpent-2-ene, we will follow these steps:

### Step 1: Understand the Structure of 2-Methylpent-2-ene
2-Methylpent-2-ene is an alkene with five carbon atoms and a double bond between the second and third carbon atoms. The structure can be represented as follows:

```
CH3
|
CH3-C=CH-CH2-CH3
```

### Step 2: Perform Ozonolysis
Ozonolysis involves the reaction of an alkene with ozone (O3) to form an ozonide intermediate. In the case of 2-methylpent-2-ene, the double bond will be cleaved, and we will form two carbonyl compounds.

### Step 3: Identify the Products
When the double bond is cleaved, we will get two fragments. The ozonolysis of 2-methylpent-2-ene will yield:

1. One fragment will be a carbonyl compound (aldehyde or ketone) from the left side of the double bond.
2. The other fragment will be another carbonyl compound from the right side of the double bond.

### Step 4: Determine the Specific Products
For 2-methylpent-2-ene, the ozonolysis will yield:
- From the left side: 2-methylbutanal (an aldehyde)
- From the right side: 3-pentanone (a ketone)

### Step 5: Reduction of Ozonides
In reductive ozonolysis, the ozonide formed is reduced using zinc and water (Zn/H2O), which will convert the ozonide into the corresponding carbonyl compounds.

### Final Products
Thus, the final products of the reductive ozonolysis of 2-methylpent-2-ene are:
- 2-methylbutanal
- 3-pentanone

### Summary
The products obtained from the reductive ozonolysis of 2-methylpent-2-ene are 2-methylbutanal and 3-pentanone.

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