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The enthalpy of vaporisation of liquid w...

The enthalpy of vaporisation of liquid water using the data
`H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l)` , `DeltaH=-285.77 kJ//mol`
`H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(g)`, `DeltaH=-241.84 kJ//mol`

A

`+43.93`

B

`-43.93`

C

`+527.61`

D

`-527.61`

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The correct Answer is:
A
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The enthalpy of vapourisation of liquid water using the data : H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(l) , Delta =-285.77 KJ mol^(-1) H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(g) , Delta H=-241.84 KJ mol^(-1)

H_(2)(g)+(1)/(2)O_(2)(g)rarr2H_(2)O(l), DeltaH =- 286 kJ 2H_(2)(g)+O_(2)(g)rarr2H_(2)O(l)……………kJ(+-?)

H_(2)O(g)+(1)/(2)O_(2)(g)toH_(2)O(g)," "DeltaH=x H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l)," "DeltaH=y heat of vaporization of water is:

The enthalpy of the reaction H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(g) is DeltaH_(1) and that of H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l) is DeltaH_(2) . Then

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