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A particle is projected with velocity 2 ...

A particle is projected with velocity `2 sqrt(gh)` so that it just clears two walls of equal height h which are at a distance 2h from each other. Show that the time of passing between the walls is `2 sqrt(h//g)`.

A

`(2h)/(g)`

B

`sqrt((2h)/(g))`

C

`sqrt((h)/(g))`

D

`2sqrt((h)/(g))`

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The correct Answer is:
D
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