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The lattice energy of solid NaCl is 180K...

The lattice energy of solid `NaCl` is `180K. Cal mol^(-1)`. The dissolution of the solid in water in the form of ions is endothermic to the extent of `1 K.cal mol^(-1)`. If the hydration energies of `Na^(+)` and `Cl^(-)` are in ratio `6 : 5`, what is the enthalpy of hydration of `Na^(+)` ion

A

`-"8.5 kcal mol"^(-1)`

B

`-"97.64 kcal mol"^(-1)`

C

`+"82.6 kcal mol"^(-1)`

D

`+"100 kcal mol"^(-1)`

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The correct Answer is:
B
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