An electron of mass m has de Broglie wavelength `lambda` when accelerated through a potential difference V . When a proton of mass M is accelerated through a potential difference 9V, the de Broglie wavelength associated with it will be (Assume that wavelength is determined at low voltage ) .

Options

A. `(lambda)/(3)sqrt((M)/(m))`
B. `(lambda)/(3).(M)/(m)`
C. `(lambda)/(3)sqrt((m)/(M))`
D. `(lambda)/(3).(m)/(M)`

Answer

C