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Why is SiCl(4) readily hydrolysed but C ...

Why is `SiCl_(4)` readily hydrolysed but `C Cl_(4)` is resistant to hydrolysis?

A

`Si-Cl` bond is weaker than `C-Cl` bond

B

`SiCl_(4)` can form hydrogen bonds

C

`SiCl_(4)` is covalent

D

`Si` can extent its coordination number beyound four

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The correct Answer is:
D
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Explain why SF_(4) is easily hydrolysed, whereas SF_(6) is resistant to hydrolysis ?

All the elements of group 14 form tetranaldes of general formula MX_(4) which are compounds (except SnF_(4) and PbF_(4) ) and have tetrahedral structure. The stability of these tetrahaldes dec reases as we move from C to Pb. The of MX_(2) increases as we move from C to Pb. Tetrahaldes are convalent compounds while dhalides are ionic. SiCl_(4) is easily hydrolysed but C Cl_(4) is not. this is because

SiCl_(4) on hydrolysis gives:

Why is SF_(4) easily hydrolysed while the hydrolysis while the hydrolysis of SF_(6) is difficult ?

C Cl_(4) is inert towards hydrolysis but SiCl_(4) is readily hydrolysed because

Give hydrolysis product of C Cl_(4) .

C Cl_(4) does not show hydrolysis but SiCl_(4) is readily hydrolysed because:

C Cl_(4) is inert towards hydrolysis but SiCl_(4) is readily hydrolysed b ecause:

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