For the reaction: `I^(-)+ClO_(3)^(-)+H_(2)SO_(4)toCl^(-)+HSO_(4)^(-)+I_(2)` The correct statement(s) in the balanced equation is/are
(1) Stoichiometric coefficient of `HSO_(4)^(-)` is 6
(2) Iodide is oxidized.
(3) Oxidation number of chlorine changes by 5 units
(4) `H_(2)O` is one of the products

Options

A. 1, 2
B. 1,4
C. 1, 2, 3
D. 1, 2, 4

Answer

To solve the question regarding the reaction \( I^- + ClO_3^- + H_2SO_4 \rightarrow Cl^- + HSO_4^- + I_2 \), we will analyze each statement step by step.

### Step 1: Write the unbalanced reaction
The unbalanced reaction is:
\[ I^- + ClO_3^- + H_2SO_4 \rightarrow Cl^- + HSO_4^- + I_2 \]

### Step 2: Identify oxidation states
- For \( I^- \): Oxidation state is -1.
- For \( I_2 \): Oxidation state is 0.
- For \( ClO_3^- \): The oxidation state of Cl can be calculated as follows:
\[ x + 3(-2) = -1 \]
\[ x - 6 = -1 \]
\[ x = +5 \]
- For \( Cl^- \): Oxidation state is -1.

### Step 3: Determine changes in oxidation states
- Iodine is oxidized from -1 in \( I^- \) to 0 in \( I_2 \) (oxidation).
- Chlorine is reduced from +5 in \( ClO_3^- \) to -1 in \( Cl^- \) (reduction).

### Step 4: Balance the reaction
To balance the reaction, we need to ensure that the number of atoms and charges are equal on both sides. The balanced reaction can be written as:
\[ 6 I^- + ClO_3^- + 6 H_2SO_4 \rightarrow 3 I_2 + Cl^- + 6 HSO_4^- \]

### Step 5: Analyze the statements
1. **Stoichiometric coefficient of \( HSO_4^- \) is 6**: This statement is correct as we have 6 \( HSO_4^- \) on the product side.
2. **Iodide is oxidized**: This statement is correct since \( I^- \) goes from -1 to 0.
3. **Oxidation number of chlorine changes by 5 units**: This statement is correct as Cl changes from +5 to -1, which is a change of 6 units.
4. **\( H_2O \) is one of the products**: This statement is incorrect as there is no \( H_2O \) produced in the balanced reaction.

### Final Conclusion
The correct statements are:
- (1) Stoichiometric coefficient of \( HSO_4^- \) is 6.
- (2) Iodide is oxidized.
- (3) Oxidation number of chlorine changes by 6 units.
- (4) \( H_2O \) is not one of the products.

### Summary of Correct Statements
- **Correct Statements**: 1, 2, and 3.
- **Incorrect Statement**: 4.