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What will be the relation between the T(...

What will be the relation between the `T_(1)` of gas 1 with `M_(1)=56` and `T_(2)` of gas 2 with `M_(2)=44` if the average speed of gas 1 is equal to most probable speed of gas 2?

A

`T_(1)=T_(2)^(2)`

B

`T_(1)=T_(2)`

C

`T_(1)=(T_(2))^((1)/(2))`

D

`T_(1)=(1)/(T_(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to establish the relationship between the temperatures \( T_1 \) and \( T_2 \) of two gases based on their average and most probable speeds. ### Step-by-Step Solution: 1. **Identify the Given Information:** - Molar mass of gas 1, \( M_1 = 56 \) g/mol - Molar mass of gas 2, \( M_2 = 44 \) g/mol - Average speed of gas 1 is equal to the most probable speed of gas 2. 2. **Write the Formulas for Speeds:** - The average speed \( V_{avg} \) of a gas is given by: \[ V_{avg} = \sqrt{\frac{8RT}{\pi M}} \] - The most probable speed \( V_{mp} \) of a gas is given by: \[ V_{mp} = \sqrt{\frac{2RT}{M}} \] 3. **Set Up the Equation:** - According to the problem, we have: \[ V_{avg} (gas 1) = V_{mp} (gas 2) \] - Substituting the formulas: \[ \sqrt{\frac{8RT_1}{\pi M_1}} = \sqrt{\frac{2RT_2}{M_2}} \] 4. **Square Both Sides:** - To eliminate the square roots, we square both sides: \[ \frac{8RT_1}{\pi M_1} = \frac{2RT_2}{M_2} \] 5. **Cancel Out the Universal Gas Constant \( R \):** - Since \( R \) is present on both sides, we can cancel it out: \[ \frac{8T_1}{\pi M_1} = \frac{2T_2}{M_2} \] 6. **Substitute the Molar Mass Values:** - Plugging in \( M_1 = 56 \) and \( M_2 = 44 \): \[ \frac{8T_1}{\pi \cdot 56} = \frac{2T_2}{44} \] 7. **Cross-Multiply to Solve for \( T_1 \) and \( T_2 \):** - Cross-multiplying gives: \[ 8T_1 \cdot 44 = 2T_2 \cdot \pi \cdot 56 \] - Simplifying this: \[ 352T_1 = 112\pi T_2 \] 8. **Isolate \( T_1 \) in Terms of \( T_2 \):** - Dividing both sides by 352: \[ T_1 = \frac{112\pi T_2}{352} \] - Simplifying further: \[ T_1 = \frac{112\pi}{352} T_2 = \frac{\pi}{3.142857} T_2 \approx 0.3183 T_2 \] ### Final Relation: Thus, the relation between \( T_1 \) and \( T_2 \) is: \[ T_1 \approx 0.3183 T_2 \]
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