The number of alkenes (including stereoisomers) which can produce 2 - butanol by the successive treatment of (i) `B_(2)H_(6)` in tetrahydrofuran solvent and (ii) alkaline `H_(2)O_(2)` solution is/are

Answer

To determine the number of alkenes (including stereoisomers) that can produce 2-butanol through the hydroboration-oxidation method, we will follow these steps:

### Step 1: Understand the Hydroboration-Oxidation Mechanism
The hydroboration-oxidation reaction involves the addition of boron to the alkene followed by oxidation to form an alcohol. In this case, we will be using B2H6 (diborane) in tetrahydrofuran (THF) followed by alkaline H2O2.

### Step 2: Identify the Structure of 2-Butanol
2-Butanol has the structure CH3-CH(OH)-CH2-CH3. The hydroxyl (OH) group must be added to the second carbon of the butane chain, which is achieved through the anti-Markovnikov addition of boron.

### Step 3: Determine the Required Alkene Structure
To produce 2-butanol, we need to find alkenes that can lead to this product. The double bond must be positioned such that after hydroboration and oxidation, the OH group ends up on the second carbon.

### Step 4: Identify Possible Alkenes
1. **But-2-ene (Cis and Trans)**:
- **Cis-But-2-ene**: CH3-CH=CH-CH3 (cis configuration)
- **Trans-But-2-ene**: CH3-CH=CH-CH3 (trans configuration)
Both of these alkenes will yield 2-butanol upon hydroboration and oxidation.

2. **But-1-ene**:
- **But-1-ene**: CH2=CH-CH2-CH3
This alkene can also yield 2-butanol through the same mechanism.

### Step 5: Count the Alkenes and Their Stereoisomers
- **Cis-But-2-ene**: 1
- **Trans-But-2-ene**: 1
- **But-1-ene**: 1

Thus, we have a total of 3 alkenes that can produce 2-butanol, including stereoisomers.

### Final Answer
The total number of alkenes (including stereoisomers) that can produce 2-butanol is **3**.

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