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The statement ~prarr(qrarrp) is equivale...

The statement `~prarr(qrarrp)` is equivalent to

A

`prarr(prarrq)`

B

`prarr(p vv q)`

C

`q rarrp`

D

`q rarr (prarrq)`

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The correct Answer is:
To solve the problem of determining the equivalence of the statement `~p → (q → p)`, we can follow these steps: ### Step 1: Understand the Statement The statement `~p → (q → p)` can be interpreted as "if not p, then (if q then p)". We need to analyze this statement logically. ### Step 2: Rewrite the Implications Recall that the implication \( A \to B \) can be rewritten as \( \neg A \lor B \). Thus, we can rewrite the statement: - \( q \to p \) can be rewritten as \( \neg q \lor p \). - Therefore, \( ~p → (q → p) \) becomes \( \neg p \to (\neg q \lor p) \). ### Step 3: Rewrite the Negation Now, applying the implication transformation to \( \neg p \to (\neg q \lor p) \): - This becomes \( \neg(\neg p) \lor (\neg q \lor p) \). - Simplifying \( \neg(\neg p) \) gives us \( p \), so we have \( p \lor (\neg q \lor p) \). ### Step 4: Simplify the Expression Using the associative and commutative properties of logical disjunction (OR): - We can simplify \( p \lor (\neg q \lor p) \) to \( p \lor \neg q \). ### Step 5: Final Result Thus, the original statement `~p → (q → p)` simplifies to \( p \lor \neg q \). ### Conclusion The statement `~p → (q → p)` is equivalent to \( p \lor \neg q \).
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