Electronic configuration of few elements are given below. Mark the incorrect match.

Options

A. `1s^(2)2s^(2)2p^(5)`, Most electronegative element
B. `1s^(2)2s^(2)2p^(3)`, An element, belonging to 3 period and 5 group
C. `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(8)4s^(2)`, A d - block element
D. `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)`, An element from 18 group

Answer

To solve the question of identifying the incorrect match among the electronic configurations provided, we will analyze each option step by step.

### Step-by-Step Solution:

1. **Identify the Electronic Configurations**:
- We need to analyze the electronic configurations given in each option and determine the corresponding element and its group and period.

2. **Analyze Option 1**:
- Electronic Configuration: 1s² 2s² 2p⁵
- Total Electrons: 2 + 2 + 5 = 9
- Element: The element with atomic number 9 is Fluorine (F).
- Group: 17 (Group of Halogens)
- Period: 2
- **Conclusion**: This match is correct.

3. **Analyze Option 2**:
- Electronic Configuration: 1s² 2s² 2p³
- Total Electrons: 2 + 2 + 3 = 7
- Element: The element with atomic number 7 is Nitrogen (N).
- Group: 15 (Group of Pnictogens)
- Period: 2
- **Conclusion**: This match is correct.

4. **Analyze Option 3**:
- Electronic Configuration: 1s² 2s² 2p⁶ 3s² 3p⁶
- Total Electrons: 2 + 2 + 6 + 2 + 6 = 18
- Element: The element with atomic number 18 is Argon (Ar).
- Group: 18 (Noble Gases)
- Period: 3
- **Conclusion**: This match is correct.

5. **Analyze Option 4**:
- Electronic Configuration: 1s² 2s² 2p⁶ 3s² 3p¹
- Total Electrons: 2 + 2 + 6 + 2 + 1 = 13
- Element: The element with atomic number 13 is Aluminum (Al).
- Group: 13 (Group of Boron)
- Period: 3
- **Conclusion**: This match is incorrect as it states it belongs to the 5th group, but it actually belongs to the 13th group.

### Final Answer:
The incorrect match is **Option 4**.