Given below are the structure of few compounds with molecular formula `C_(4)H_(10)O`. Select metamers from these structure.
(i) `CH_(3)-O-CH_(2)CH_(2)CH_(3)`
(ii) `CH_(3)CH_(2)CH_(2)CH_(2)OH`
(iii) `CH_(3)-CH_(2)-O-CH_(2)-CH_(3)`
(iv) `CH_(3)-underset(OH)underset("| ")"CH"-CH_(2)-CH_(3)`

Options

A. (i) and (ii)
B. (ii) and (iii)
C. (i) and (iii)
D. (ii) and (iv)

Answer

To determine the metamers among the given compounds with the molecular formula C₄H₁₀O, we need to identify compounds that have the same molecular formula but differ in the structure around the heteroatom (in this case, oxygen).

Let's analyze each compound:

1. **Compound (i)**: `CH₃-O-CH₂CH₂CH₃`
- This is an ether (specifically, an alkyl ether).

2. **Compound (ii)**: `CH₃CH₂CH₂CH₂OH`
- This is a primary alcohol.

3. **Compound (iii)**: `CH₃-CH₂-O-CH₂-CH₃`
- This is also an ether.

4. **Compound (iv)**: `CH₃-CH(OH)-CH₂-CH₃`
- This is a secondary alcohol.

### Step-by-Step Solution:

1. **Identify the functional groups**:
- Compound (i) and (iii) are ethers.
- Compound (ii) and (iv) are alcohols.

2. **Check for metamers**:
- Metamers are structural isomers that differ in the arrangement of carbon chains around the heteroatom (O in this case).
- Compare (i) and (iii):
- Both are ethers and have different alkyl groups attached to the oxygen atom. Therefore, they are metamers.
- Compare (ii) and (iv):
- Both are alcohols but do not have the same structural arrangement around the oxygen. They are not metamers since they belong to different functional groups.

3. **Conclusion**:
- The metamers among the given compounds are **(i) and (iii)**.

### Final Answer:
The metamers from the given structures are (i) `CH₃-O-CH₂CH₂CH₃` and (iii) `CH₃-CH₂-O-CH₂-CH₃`.