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If the variate of a distribution takes t...

If the variate of a distribution takes the values `1^(2), 2^(2), 3^(2),….n^(2)` with frequencies `n, n-1, n-2,….3,2,1` respectively, then the mean value of the distribution is

A

`(n(n+2))/(3)`

B

`(n(n+1)(n+2))/(6)`

C

`(n+2)/(3)`

D

`((n+1)(n+2))/(6)`

Text Solution

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The correct Answer is:
D
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