Identify X and Y in the following reaction `BCl_(3)+NH_(4)Cl overset(140^(@)C//C_(6)H_(5)Cl)rarr X overset(NaBH_(4))rarr Y`

Options

A. `X=NaBO_(2), Y=B_(2)O_(3)`
B. `X=Na_(2)B_(4)O_(7), Y=H_(3)BO_(3)`
C. `X=BN, Y=[NH_(4)]^(+)[BCl_(4)]^(-)`
D. `X=B_(3)N_(3)H_(3)Cl_(3), Y=B_(3)N_(3)H_(6)`

Answer

To solve the problem, we need to identify the compounds X and Y in the given reaction sequence. Let's break down the reaction step by step.

### Step 1: Identify the Reaction of BCl₃ with NH₄Cl
The first part of the reaction involves the interaction of boron trichloride (BCl₃) with ammonium chloride (NH₄Cl) at a temperature of 140°C in the presence of chlorobenzene (C₆H₅Cl).

The reaction can be summarized as:
\[ \text{BCl}_3 + \text{NH}_4\text{Cl} \rightarrow \text{B}_3\text{N}_3\text{H}_3\text{Cl}_3 \]

This product, B₃N₃H₃Cl₃, is known as borazine, which is often referred to as "inorganic benzene" due to its structural similarity to benzene.

### Step 2: Identify Compound X
From the first step, we can conclude that:
- **X = B₃N₃H₃Cl₃**

### Step 3: Reduction of X with NaBH₄
Next, we need to reduce compound X (B₃N₃H₃Cl₃) using sodium borohydride (NaBH₄). The reduction process typically involves the replacement of chlorine atoms with hydrogen atoms.

The reduction can be summarized as:
\[ \text{B}_3\text{N}_3\text{H}_3\text{Cl}_3 + \text{NaBH}_4 \rightarrow \text{B}_3\text{N}_3\text{H}_6 \]

This product, B₃N₃H₆, is also borazine but in a fully hydrogenated form, which can be seen as a derivative of borazine.

### Step 4: Identify Compound Y
From the reduction step, we find that:
- **Y = B₃N₃H₆**

### Final Answer
Thus, the identified compounds are:
- **X = B₃N₃H₃Cl₃**
- **Y = B₃N₃H₆**