Given below are two reactions of water with sodium and carbon dioxide. What is the nature of water is these reactions?
(i) `2Na_2H_(2)Orarr 2NaOH+H_(2)`
(ii) `6CO_(2)+12H_(2)Orarr C_(6)H_(12)O_(6)+6H_(2)O+6O_(2)`

Options

A. In (ii) water acts as an oxidising agent and in (ii) it acts as a reducing agent
B. In (i) water acts an an oxidising agent while in (ii) it acts as a reducing agent
C. In both, (i) and (ii) hydrogen acts as a reducing agent
D. In both, (i) and (ii) hydrogen acts as a reducing agent

Answer

To determine the nature of water in the given reactions, we need to analyze each reaction step by step.

### Reaction 1:
\[ 2Na + 2H_2O \rightarrow 2NaOH + H_2 \]

1. **Identify the oxidation states**:
- In water (\(H_2O\)), the oxidation state of hydrogen (H) is +1 and oxygen (O) is -2.
- In sodium hydroxide (\(NaOH\)), sodium (Na) is +1, oxygen is -2, and hydrogen is +1.
- In hydrogen gas (\(H_2\)), the oxidation state of hydrogen is 0.

2. **Determine the changes in oxidation states**:
- Sodium (Na) is oxidized from 0 (elemental state) to +1 in \(NaOH\).
- Hydrogen in water is reduced from +1 to 0 in \(H_2\).

3. **Conclusion for Reaction 1**:
- Since water is facilitating the reduction of hydrogen (decreasing its oxidation state), it acts as an **oxidizing agent** in this reaction.

### Reaction 2:
\[ 6CO_2 + 12H_2O \rightarrow C_6H_{12}O_6 + 6H_2O + 6O_2 \]

1. **Identify the oxidation states**:
- In carbon dioxide (\(CO_2\)), carbon (C) is +4 and oxygen is -2.
- In glucose (\(C_6H_{12}O_6\)), carbon is in various oxidation states, but overall, it is lower than +4.
- In water (\(H_2O\)), hydrogen is +1 and oxygen is -2.
- In oxygen gas (\(O_2\)), the oxidation state of oxygen is 0.

2. **Determine the changes in oxidation states**:
- Carbon in \(CO_2\) is reduced from +4 to a lower oxidation state in glucose.
- Oxygen in water is oxidized from -2 to 0 in \(O_2\).

3. **Conclusion for Reaction 2**:
- Since water is facilitating the oxidation of oxygen (increasing its oxidation state), it acts as a **reducing agent** in this reaction.

### Summary:
- In the first reaction, water acts as an **oxidizing agent**.
- In the second reaction, water acts as a **reducing agent**.

### Final Answer:
Water acts as an oxidizing agent in the first reaction and as a reducing agent in the second reaction.

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