Complete the missing links
`CH_(3)CHBrCH_(3) overset("alc. KOH")rarr Xoverset("HBr, Peroxiden")rarr Y overset(CH_(3)Ona)rarr Z`

Options

A. `{:("X","Y","Z"),(CH_(3)CH=CH_(2),CH_(3)CH(Br)CH_(2)Br,CH_(3)CH(OH)CH_(3)):}`
B. `{:("X","Y","Z"),(CH_(3)CH=CH_(2),CH_(3)CH_(2)CH_(2)Br,CH_(3)CH_(2)OCH_(2)CH_(3)):}`
C. `{:("X","Y","Z"),(CH_(3)CH=CH_(2),CH_(3)CH(Br)CH_(3),CH_(3)CH_(2)OCH_(2)CH_(3)):}`
D. `{:("X","Y","Z"),(CH_(3)CH=CH_(2),CH_(3)CH_(2)CH_(2)Br,CH_(3)CH_(2)CH_(2)OCH_(3)):}`

Answer

To solve the problem, we need to identify the missing compounds X, Y, and Z in the given reaction sequence starting from CH₃CHBrCH₃. Let's break it down step by step.

### Step 1: Identify the reaction with alcoholic KOH
The first transformation involves the compound CH₃CHBrCH₃ reacting with alcoholic KOH. Alcoholic KOH is a strong base that promotes elimination reactions (dehydrohalogenation).

**Reaction:**
- CH₃CHBrCH₃ + alc. KOH → CH₃CH=CH₂ + HBr

Here, the bromine (Br) is eliminated along with a hydrogen atom (H) from the adjacent carbon, resulting in the formation of an alkene.

**Missing Compound X:**
- X = CH₃CH=CH₂ (Propene)

### Step 2: Reaction with HBr in the presence of peroxide
Next, we take the alkene (X = CH₃CH=CH₂) and react it with HBr in the presence of peroxide. The presence of peroxide leads to an anti-Markovnikov addition of HBr to the alkene.

**Reaction:**
- CH₃CH=CH₂ + HBr (in presence of peroxide) → CH₃CHBrCH₃

In this case, the bromine (Br) will add to the less substituted carbon atom of the alkene.

**Missing Compound Y:**
- Y = CH₃CHBrCH₂ (Bromo-propane)

### Step 3: Reaction with CH₃O⁻Na⁺
Finally, we react compound Y (CH₃CHBrCH₂) with sodium methoxide (CH₃O⁻Na⁺). This is a nucleophilic substitution reaction where the methoxide ion (CH₃O⁻) will replace the bromine atom.

**Reaction:**
- CH₃CHBrCH₂ + CH₃O⁻ → CH₃CH₂CH₂OCH₃ + Br⁻

This results in the formation of an ether.

**Missing Compound Z:**
- Z = CH₃CH₂CH₂OCH₃ (Methyl propyl ether)

### Summary of the Missing Compounds
- X = CH₃CH=CH₂ (Propene)
- Y = CH₃CHBrCH₂ (Bromo-propane)
- Z = CH₃CH₂CH₂OCH₃ (Methyl propyl ether)