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the solution of the differential equatio...

the solution of the differential equation ` dy/dx = ax + b` , `a!=0` represents

A

a parabola

B

an ellipse

C

a circle

D

a hyperbola

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The correct Answer is:
To solve the differential equation \(\frac{dy}{dx} = ax + b\) where \(a \neq 0\), we will integrate both sides step by step. ### Step 1: Rewrite the Differential Equation We start with the given differential equation: \[ \frac{dy}{dx} = ax + b \] ### Step 2: Separate Variables We can rewrite this as: \[ dy = (ax + b)dx \] ### Step 3: Integrate Both Sides Now, we will integrate both sides. The left side integrates to \(y\) and the right side requires us to integrate \(ax + b\): \[ \int dy = \int (ax + b)dx \] ### Step 4: Perform the Integration The integration of the left side gives: \[ y = \int dy = y \] For the right side, we integrate: \[ \int (ax + b)dx = \frac{a}{2}x^2 + bx + C \] where \(C\) is the constant of integration. ### Step 5: Combine the Results Combining both results, we have: \[ y = \frac{a}{2}x^2 + bx + C \] ### Step 6: Identify the Type of Function The equation \(y = \frac{a}{2}x^2 + bx + C\) is a quadratic function in \(x\), which represents a parabola. ### Conclusion Thus, the solution of the differential equation \(\frac{dy}{dx} = ax + b\) where \(a \neq 0\) represents a parabola.
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