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Let : P(1):3y+z+1=0 and P(2):2x-y+3z-7=0...

Let : `P_(1):3y+z+1=0 and P_(2):2x-y+3z-7=0` and the equation of line AB is `(x-1)/(2)=(y-3)/(-1)=(z-4)/(3)` in 3D space. Shortest distance between the line of intersection of planes `P_(1) and P_(2)` and the line AB is equal to

A

`(7)/(sqrt(10))" units"`

B

`7sqrt((2)/(5))" units"`

C

`(6)/(sqrt(10))" units"`

D

`2sqrt((2)/(5))" units"`

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The correct Answer is:
B
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