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If A and B are square matrices such that...

If A and B are square matrices such that `A^(2020)=O and AB=A+B`, then `|B|` is equal to (where, O is a null matrix)

A

0

B

1

C

`-1`

D

4

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the given conditions step by step. ### Step-by-Step Solution: 1. **Given Conditions**: We have two square matrices \( A \) and \( B \) such that: \[ A^{2020} = O \quad \text{(where \( O \) is the null matrix)} \] and \[ AB = A + B. \] 2. **Determinant of \( A^{2020} \)**: Since \( A^{2020} = O \), we can take the determinant of both sides: \[ |A^{2020}| = |O|. \] The determinant of the null matrix \( O \) is 0: \[ |O| = 0. \] Therefore, \[ |A^{2020}| = 0. \] 3. **Using the Property of Determinants**: We know that the determinant of a matrix raised to a power is equal to the determinant of the matrix raised to that power: \[ |A^{2020}| = |A|^{2020}. \] Thus, we have: \[ |A|^{2020} = 0. \] 4. **Conclusion about \( |A| \)**: The only way for \( |A|^{2020} = 0 \) is if \( |A| = 0 \). Therefore, we conclude: \[ |A| = 0. \] 5. **Using the Second Condition \( AB = A + B \)**: Now, we take the determinant of both sides of the equation \( AB = A + B \): \[ |AB| = |A + B|. \] 6. **Applying the Determinant Product Rule**: The determinant of a product of matrices is the product of their determinants: \[ |AB| = |A| \cdot |B|. \] Thus, we have: \[ |A| \cdot |B| = |A + B|. \] 7. **Substituting \( |A| = 0 \)**: Since we found that \( |A| = 0 \), we can substitute this into the equation: \[ 0 \cdot |B| = |A + B|. \] This simplifies to: \[ 0 = |A + B|. \] 8. **Conclusion about \( |B| \)**: The determinant \( |A + B| = 0 \) does not directly give us \( |B| \). However, since \( |A| = 0 \) and \( |AB| = |A + B| \), we can conclude that \( |B| \) must also be 0 in order for the equation to hold true. Therefore, we conclude that: \[ |B| = 0. \] ### Final Answer: \[ |B| = 0. \]
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