`underset((A))(C_(12)H_(16))overset("i) "O_(3)"ii) "Zn,H_(2)O_(2))rarr 2H_(3)C-overset(O)overset(||)C-CH_(3)+2HOOC+overset(O)overset(||)C-COOH`
What is degree of unsaturation of compound A?

Answer

To find the degree of unsaturation of compound A, which has the molecular formula \( C_{12}H_{16} \), we can use the formula for calculating the degree of unsaturation (DU):

\[ DU = \frac{1}{2} \left( 2C + 2 + N - H - X \right) \]

Where:
- \( C \) = number of carbon atoms
- \( H \) = number of hydrogen atoms
- \( N \) = number of nitrogen atoms
- \( X \) = number of halogen atoms

### Step 1: Identify the values from the molecular formula
From the molecular formula \( C_{12}H_{16} \):
- \( C = 12 \)
- \( H = 16 \)
- \( N = 0 \) (since there are no nitrogen atoms)
- \( X = 0 \) (since there are no halogen atoms)

### Step 2: Substitute the values into the formula
Now we can substitute these values into the degree of unsaturation formula:

\[ DU = \frac{1}{2} \left( 2(12) + 2 + 0 - 16 - 0 \right) \]

### Step 3: Simplify the equation
Calculating inside the parentheses:

\[ DU = \frac{1}{2} \left( 24 + 2 - 16 \right) \]

\[ DU = \frac{1}{2} \left( 10 \right) \]

\[ DU = 5 \]

### Conclusion
The degree of unsaturation of compound A is **5**.

---