A particle of mass `'m'` moves along the quarter section of the circular path whose centre is at the origin . The radius of the circular path is `'a'`. A force `vec(F)=yhat(i)-xhat(j)` newton acts on the particle, where `x,y` denote the coordinates of position of the particle. Calculate the work done by this force in taking, the particle from point, `A(a,0)` to point `B(0,a)` along the circular path.

Options

A. `pia^(2)J`
B. `(pia^(2))/(2)J`
C. `-(pia^(2))/(2)J`
D. Zero

Answer

C