How much linkage strength is present between two genes A & B, which are 6 cM far from each other in a chromosome ?

Options

A. `6%`
B. `le50%`
C. `94%`
D. Data insufficient

Answer

To determine the linkage strength between two genes A and B that are 6 centimorgans (cM) apart on a chromosome, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Centimorgans (cM)**: Centimorgans are a unit of measurement for genetic linkage. One centimorgan corresponds to a 1% chance that a crossover will occur between two genes during meiosis.

2. **Identifying the Distance**: The question states that genes A and B are 6 cM apart. This means there is a 6% chance of a crossover occurring between these two genes.

3. **Calculating Linkage Strength**: Since the distance between the two genes is given in centimorgans, the linkage strength can be directly interpreted as the percentage chance of recombination. Therefore, if the genes are 6 cM apart, the linkage strength is 6%.

4. **Conclusion**: The linkage strength between genes A and B, which are 6 cM apart, is 6%.

### Final Answer:
The linkage strength between genes A and B is **6%**.

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