When two pure pea plants one having round seeds and the other having wrinkled seeds are crossed, their offsprings have

Options

A. Large starch grain
B. Small starch grain
C. Intermediate starch grain
D. Large starch grain and intermediate starch grain is equal proportion

Answer

To solve the question regarding the offspring of two pure pea plants with round and wrinkled seeds, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Traits and Alleles**:
- Round seeds are dominant (represented by the allele **B**).
- Wrinkled seeds are recessive (represented by the allele **b**).

2. **Determine the Parental Genotypes**:
- The pure pea plant with round seeds has the genotype **BB** (homozygous dominant).
- The pure pea plant with wrinkled seeds has the genotype **bb** (homozygous recessive).

3. **Perform the Cross**:
- When these two plants are crossed, the gametes produced will be:
- From **BB**: all gametes will be **B**.
- From **bb**: all gametes will be **b**.
- Therefore, the offspring will have the genotype **Bb**.

4. **Analyze the Offspring's Phenotype**:
- The genotype **Bb** indicates that the offspring are heterozygous.
- In this case, since the trait exhibits incomplete dominance, the phenotype of the offspring will not be purely round or wrinkled but will show an intermediate trait.

5. **Conclusion**:
- The size of the starch grain in the offspring will be intermediate due to the incomplete dominance between the alleles. Thus, the correct answer is **C. Intermediate starch grain**.