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A woman with normal vision whose mother ...

A woman with normal vision whose mother was colourblind married a man with normal vision. The woman is pregnant with her first child. What is the probability that the cild will be a colour blind boy?

A

`1//4`

B

`1//2`

C

`3//4`

D

0

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the genetic background of the individuals involved and use a Punnett square to determine the probability of having a colorblind boy. ### Step-by-Step Solution: 1. **Identify the Genetic Makeup of the Woman**: - The woman has normal vision but her mother is colorblind. Since colorblindness is an X-linked recessive trait, this means that the woman must carry one normal vision allele (X^N) and one colorblind allele (X^c). Therefore, her genotype is X^N X^c. 2. **Identify the Genetic Makeup of the Man**: - The man has normal vision. Since colorblindness is X-linked and he has normal vision, his genotype is X^N Y. 3. **Set Up the Punnett Square**: - We will set up a Punnett square to find the possible genotypes of their children. The woman can contribute either X^N or X^c, and the man can contribute either X^N or Y. | | X^N (from father) | Y (from father) | |---------|-------------------|------------------| | X^N (from mother) | X^N X^N (Normal girl) | X^N Y (Normal boy) | | X^c (from mother) | X^c X^N (Carrier girl) | X^c Y (Colorblind boy) | 4. **Determine the Possible Outcomes**: - From the Punnett square, we have the following possible genotypes for the children: - X^N X^N: Normal girl - X^N Y: Normal boy - X^c X^N: Carrier girl (normal vision) - X^c Y: Colorblind boy 5. **Count the Outcomes**: - There are 4 possible outcomes: - 1 Normal girl (X^N X^N) - 1 Normal boy (X^N Y) - 1 Carrier girl (X^c X^N) - 1 Colorblind boy (X^c Y) 6. **Calculate the Probability of a Colorblind Boy**: - Out of the 4 possible outcomes, only 1 outcome is a colorblind boy (X^c Y). - Therefore, the probability of having a colorblind boy is 1 out of 4, or 1/4. ### Final Answer: The probability that the child will be a colorblind boy is **1/4**.
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