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If the diameter of a cylinder is 12.6 pm...

If the diameter of a cylinder is `12.6 pm0.1` cm and its height is `34.2 pm0.1` , then find the volume of the cylinder to the nearest significant figure .

A

`426.4pm81 cm^3`

B

`4260pm81cm^3`

C

`4300pm80cm^3`

D

`4260pm80cm^3`

Text Solution

AI Generated Solution

The correct Answer is:
To find the volume of the cylinder given its diameter and height, we will follow these steps: ### Step 1: Calculate the Radius The diameter of the cylinder is given as \(12.6 \pm 0.1 \, \text{cm}\). To find the radius, we divide the diameter by 2. \[ r = \frac{12.6}{2} = 6.3 \, \text{cm} \] The uncertainty in the radius can be calculated as half of the uncertainty in the diameter: \[ \Delta r = \frac{0.1}{2} = 0.05 \, \text{cm} \] ### Step 2: Write the Volume Formula The volume \(V\) of a cylinder is given by the formula: \[ V = \pi r^2 h \] Where: - \(r\) is the radius - \(h\) is the height ### Step 3: Substitute the Values The height of the cylinder is given as \(34.2 \pm 0.1 \, \text{cm}\). We can use the height value directly for volume calculation: \[ h = 34.2 \, \text{cm} \] Now substituting the values into the volume formula: \[ V = \pi (6.3)^2 (34.2) \] Using \(\pi \approx \frac{22}{7}\): \[ V \approx \frac{22}{7} \times (6.3)^2 \times 34.2 \] ### Step 4: Calculate \(r^2\) First, calculate \(r^2\): \[ (6.3)^2 = 39.69 \] ### Step 5: Calculate the Volume Now substitute \(r^2\) back into the volume equation: \[ V \approx \frac{22}{7} \times 39.69 \times 34.2 \] Calculating this step by step: 1. Calculate \(39.69 \times 34.2\): \[ 39.69 \times 34.2 \approx 1355.658 \] 2. Now multiply by \(\frac{22}{7}\): \[ V \approx \frac{22 \times 1355.658}{7} \approx \frac{29826.476}{7} \approx 4260.93 \, \text{cm}^3 \] ### Step 6: Round to the Nearest Significant Figure The volume calculated is approximately \(4260.93 \, \text{cm}^3\). Rounding this to the nearest significant figure gives: \[ V \approx 4260 \, \text{cm}^3 \] ### Final Answer The volume of the cylinder to the nearest significant figure is: \[ \boxed{4260 \, \text{cm}^3} \]
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