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Two materials having coefficients of thermal conductivity ‘3 K’ and ‘K’ and thickness ‘d’ and ‘3 d’, respectively, are joined to form a slab as shown in the figure. The temperatures of the outer surfaces are `theta_(2)` and `theta_(1)` respectively, `(theta_(2) gt theta_(1))` The temperature at the interface is:

A

`(theta_2+theta_1)/2 `

B

`(theta_1)/6+(5theta_2)/6 `

C

`(theta_1)/3+(2theta_2)/3 `

D

`(theta_1)/10+(9theta_2)/10 `

Text Solution

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The correct Answer is:
D
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