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0.1 mole of CH(3)NH(2) (K(b)=5xx10^(-4))...

`0.1` mole of `CH_(3)NH_(2) (K_(b)=5xx10^(-4))` is mixed with `0.08` mole of `HCl` and diluted to one litre. The `[H^(+)]` in solution is

A

`8xx10^(-2)`

B

`2xx10^(-11)`

C

`1.23xx10^(-4)`

D

`8xx10^(-11)`

Text Solution

Verified by Experts

The correct Answer is:
D
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