`"CCl"_3CH=CH_2overset(Cl_2+H_2O)rarrA,` is

Options

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Answer

To solve the problem, we need to analyze the reaction of the compound \( \text{CCl}_3\text{CH}=\text{CH}_2 \) with \( \text{Cl}_2 \) in the presence of water. Let's break it down step by step.

### Step 1: Identify the Reactants
The reactant is \( \text{CCl}_3\text{CH}=\text{CH}_2 \), which is an alkene with a double bond between the second and third carbons. The presence of \( \text{Cl}_2 \) and \( \text{H}_2\text{O} \) indicates that we will be performing an electrophilic addition reaction.

**Hint:** Look for the functional groups and the type of reaction taking place (electrophilic addition).

### Step 2: Understand the Reaction Mechanism
In the presence of \( \text{Cl}_2 \) and \( \text{H}_2\text{O} \), the \( \text{Cl}_2 \) will dissociate to form \( \text{Cl}^+ \) (electrophile) and \( \text{Cl}^- \). The water will generate hypochlorous acid \( \text{HOCl} \), which can also participate in the reaction.

**Hint:** Recognize that alkenes react with electrophiles due to their nucleophilic nature.

### Step 3: Electrophilic Attack
The \( \text{Cl}^+ \) will attack the double bond of the alkene. The double bond can attack the electrophile at either carbon, leading to the formation of two possible carbocations:

1. If \( \text{Cl}^+ \) adds to the first carbon (C1), we get a secondary carbocation.
2. If \( \text{Cl}^+ \) adds to the second carbon (C2), we get a primary carbocation.

**Hint:** Consider the stability of the carbocations formed during the reaction.

### Step 4: Determine the More Stable Carbocation
The secondary carbocation (formed by adding \( \text{Cl}^+ \) to C1) is more stable than the primary carbocation (formed by adding \( \text{Cl}^+ \) to C2) due to hyperconjugation and inductive effects from the \( \text{CCl}_3 \) group.

**Hint:** Stability of carbocations is key in determining the major product.

### Step 5: Nucleophilic Attack by Water
Once the more stable carbocation is formed, water (\( \text{H}_2\text{O} \)) will act as a nucleophile and attack the carbocation. This will lead to the formation of a product where one of the chlorine atoms is replaced by a hydroxyl group (\( \text{OH} \)).

**Hint:** Look for the final product structure after the nucleophilic attack.

### Step 6: Final Product Formation
The final product will be \( \text{CCl}_3\text{CH(OH)}\text{CH}_2\text{Cl} \). This product has a hydroxyl group and a chlorine atom attached to the carbon chain.

**Hint:** Check the structure of the final product against the given options to identify the correct answer.

### Conclusion
After analyzing the reaction, the major product \( A \) formed from the reaction of \( \text{CCl}_3\text{CH}=\text{CH}_2 \) with \( \text{Cl}_2 \) and \( \text{H}_2\text{O} \) is \( \text{CCl}_3\text{CH(OH)}\text{CH}_2\text{Cl} \).