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A hydroxyl acid on heating gives a 5 - m...

A hydroxyl acid on heating gives a 5 - membered lactone. The acid is

A

`CH_2OHCH_2CH_2COOH`

B

`CH_3CHOHCH_2COOH`

C

`CH_3CH_2CHOHCOOH`

D

`CH_3CHOHCHOHCOOH`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which hydroxyl acid gives a 5-membered lactone upon heating, we can follow these steps: ### Step 1: Understand the structure of a 5-membered lactone A 5-membered lactone is a cyclic ester formed from a hydroxyl acid. It consists of a ring of five atoms, including one oxygen atom and four carbon atoms. The general structure can be represented as follows: ``` O / \ C C | | C C ``` ### Step 2: Identify the components of the hydroxyl acid A hydroxyl acid contains both a hydroxyl group (-OH) and a carboxylic acid group (-COOH). For the formation of a 5-membered lactone, the hydroxyl group must be positioned such that it can react with the carboxylic acid group upon heating. ### Step 3: Analyze the given compounds We need to analyze the four given hydroxyl acids to determine which one can form a 5-membered lactone. The key points to consider are: - The presence of a -COOH group. - The presence of a -OH group. - The carbon chain length must allow for the formation of a 5-membered ring. ### Step 4: Draw the structures of the compounds 1. **Compound 1**: CH2(OH)CH2COOH 2. **Compound 2**: CH3CH(OH)CH2COOH 3. **Compound 3**: CH3CH2CH(OH)COOH 4. **Compound 4**: CH3CH2C(OH)COOH ### Step 5: Determine which compound can form a 5-membered lactone - For **Compound 1**: The structure allows for the -OH group to react with the -COOH group to form a 5-membered ring. - For **Compound 2**: The -OH is not positioned to effectively react with the -COOH group to form a 5-membered lactone. - For **Compound 3**: Similar to Compound 2, the positioning does not favor lactone formation. - For **Compound 4**: The structure does not allow for a 5-membered lactone formation. ### Step 6: Conclusion The only compound that can form a 5-membered lactone upon heating is **Compound 1** (CH2(OH)CH2COOH). Thus, the answer is: **The hydroxyl acid that gives a 5-membered lactone upon heating is Compound 1.**
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