Moment of inertia of a uniform quarter disc of radius `R` and mass `M` about an axis through its centre of mass and perpendicular to its plane is `:`

Options

A. `(MR^2)/2 - M((4R)/(3pi))^2`
B. `(MR^2)/2 - M(sqrt(2)(4R)/(3pi))^2`
C. `(MR^2)/2 - M((4R)/(2pi))^2`
D. `(MR^2)/2 - M(sqrt(2)(4R)/(3pi))^2 9/(32 pi)`

Answer

B