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An excited He^(+) ion emits two photons ...

An excited `He^(+)` ion emits two photons in succession, with wavelength 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength `lamda`, energy `E=(1240eV)/(lamda("in nm"))`

A

n= 6

B

n = 5

C

n = 7

D

n = 4

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The correct Answer is:
B
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