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When the radioactive isotope .(88)Ra^(22...

When the radioactive isotope `._(88)Ra^(228)` decays in series by the emission of `3 alpha` and `1 beta` particle, the isotope finally formed is

A

`._84X^(228)`

B

`._86X^(222)`

C

`._86X^(216)`

D

`._86X^(215)`

Text Solution

Verified by Experts

The correct Answer is:
C
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