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The height at which the acceleration due...

The height at which the acceleration due to gravity becomes `(g)/(9)` (where g =the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :

A

2R

B

`R/sqrt3`

C

`R/2`

D

`sqrt(2R)`

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The correct Answer is:
A
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