Mach the following
`{:(,"Polymer",,"Monomer"),(i,"Nylon-6",a.,"Ethene"),(ii,"Nylon-6,6",b.,"Caprolactum"),(iii,"Polythene",c.,"Hexamethylene diamine and adipic acid"):}`

Options

A. (i)-(a),(ii)-(b),(iii)-(c)
B. (i)-(a),(ii)-(c),(iii)-(b)
C. (i)-(c),(ii)-(b),(iii)-(a)
D. (i)-(b),(ii)-(c),(iii)-(a)

Answer

To solve the problem of matching the polymers with their corresponding monomers, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Polymers**: The polymers given are:
- Nylon-6
- Nylon-6,6
- Polythene

2. **Identify the Monomers**: The monomers provided are:
- Ethene
- Caprolactam
- Hexamethylene diamine and adipic acid

3. **Match Nylon-6**:
- Nylon-6 is synthesized from caprolactam. Caprolactam is a cyclic amide that opens up to form the polymer.
- Therefore, the match for Nylon-6 is **Caprolactam** (b).

4. **Match Nylon-6,6**:
- Nylon-6,6 is formed from the combination of hexamethylene diamine and adipic acid.
- Thus, the match for Nylon-6,6 is **Hexamethylene diamine and adipic acid** (c).

5. **Match Polythene**:
- Polythene is made from the polymerization of ethene (ethylene).
- Hence, the match for Polythene is **Ethene** (a).

6. **Final Matching**:
- Now we can summarize the matches:
- Nylon-6 → Caprolactam (b)
- Nylon-6,6 → Hexamethylene diamine and adipic acid (c)
- Polythene → Ethene (a)

### Final Answer:
- (i) Nylon-6 → b. Caprolactam
- (ii) Nylon-6,6 → c. Hexamethylene diamine and adipic acid
- (iii) Polythene → a. Ethene