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For the reaction N(2) + 3H(2) to 2NH(3) ...

For the reaction `N_(2) + 3H_(2) to 2NH_(3)` if
`(Delta[NH_(3)])/(Deltat) = 2 xx 10^(-4) mol L^(-1)s^(-1)`, the value of `(-Delta[H_(2)])/(Deltat)` would be

A

`1.5xx10^(-4) molL^-1s^-1`

B

`3xx10^(-4) molL^-1s^-1`

C

`4xx10^(-4) molL^-1s^-1`

D

`6.5xx10^(-4) molL^-1s^-1`

Text Solution

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The correct Answer is:
B
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NTA MOCK TESTS-NTA NEET SET 35-CHEMISTRY
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