Cell 'A' with O . P = 10 atm and T .P. = 5 atm is in contact with a cell ' B ' having O . P = 15 atm and T. P = 12 atm . The flow of water will be :

Options

A. From A to B
B. Equal flow
C. From B to A
D. No flow

Answer

To solve the problem of water flow between two cells A and B, we need to analyze the osmotic pressure (OP) and turgor pressure (TP) of both cells.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- For Cell A:
- Osmotic Pressure (OP_A) = 10 atm
- Turgor Pressure (TP_A) = 5 atm
- For Cell B:
- Osmotic Pressure (OP_B) = 15 atm
- Turgor Pressure (TP_B) = 12 atm

2. **Calculate the Diffusion Pressure (DPD) for Both Cells:**
- The formula for Diffusion Pressure Deficit (DPD) is:
\[ DPD = OP - TP \]
- For Cell A:
\[ DPD_A = OP_A - TP_A = 10 \, \text{atm} - 5 \, \text{atm} = 5 \, \text{atm} \]
- For Cell B:
\[ DPD_B = OP_B - TP_B = 15 \, \text{atm} - 12 \, \text{atm} = 3 \, \text{atm} \]

3. **Determine the Direction of Water Flow:**
- Water moves from the area of lower DPD to the area of higher DPD.
- Here, we have:
- DPD_A = 5 atm (Cell A)
- DPD_B = 3 atm (Cell B)
- Since DPD_A (5 atm) is greater than DPD_B (3 atm), water will flow from Cell A to Cell B.

4. **Conclusion:**
- Therefore, the flow of water will be from Cell A to Cell B.

### Final Answer:
Water will flow from Cell A to Cell B.