A particle of mass `'m'` moves along the quarter section of the circular path whose centre is at the origin . The radius of the circular path is `'a'`. A force `vec(F)=yhat(i)-xhat(j)` newton acts on the particle, where `x,y` denote the coordinates of position of the particle. Calculate the work done by this force in taking, the particle from point, `A(a,0)` to point `B(0,a)` along the circular path.

Options

A. `-sqrt(2)a^2J`
B. `-(pia^2)/4J`
C. `-a^2J`
D. `-(pia^2)/2J`

Answer

D