Which of the following will produce only one product on reduction with `LiAlH_4` ?

Options

A. `CH_3COOC_2H_5`
B. `CH_3COOCH_2CH_2CH_3`
C. `CH_3CH_2COOCH_2CH_3`
D. `CH_3CH_2COOCH_3`

Answer

To determine which ester will produce only one product upon reduction with Lithium Aluminum Hydride (LiAlH4), we need to analyze the structure of each ester and the products formed during the reduction process.

### Step-by-Step Solution:

1. **Identify the Esters**: We have four esters to consider:
- Ethyl acetate (CH3COOCH2CH3)
- Propyl acetate (CH3COOCH2CH2CH3)
- Ethyl propanoate (CH3CH2COOCH2CH3)
- Methyl butanoate (CH3(CH2)2COOCH3)

2. **Understand the Reduction Reaction**: LiAlH4 is a strong reducing agent that reduces esters to alcohols. The general reaction for the reduction of an ester is:
\[ RCOOR' + LiAlH4 \rightarrow RCH2OH + R'OH \]
This means that the ester is converted into two alcohols.

3. **Analyze Each Ester**:
- **Ethyl Acetate**:
- Structure: CH3COOCH2CH3
- Upon reduction, it produces ethanol (from the ethyl group) and ethanol (from the acetyl group).
- **Products**: 2 equivalents of ethanol (C2H5OH).
- **Propyl Acetate**:
- Structure: CH3COOCH2CH2CH3
- Upon reduction, it produces ethanol (from the acetyl group) and propanol (from the propyl group).
- **Products**: Ethanol (C2H5OH) and propanol (C3H7OH).
- **Ethyl Propanoate**:
- Structure: CH3CH2COOCH2CH3
- Upon reduction, it produces propanol (from the propanoate) and ethanol (from the ethyl group).
- **Products**: Propanol (C3H7OH) and ethanol (C2H5OH).
- **Methyl Butanoate**:
- Structure: CH3(CH2)2COOCH3
- Upon reduction, it produces butanol (from the butanoate) and methanol (from the methyl group).
- **Products**: Butanol (C4H9OH) and methanol (CH3OH).

4. **Conclusion**: The only ester that produces only one product (2 equivalents of the same alcohol) upon reduction is **Ethyl Acetate**.

### Final Answer:
**Ethyl acetate produces only one product (2 equivalents of ethanol) upon reduction with LiAlH4.**

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