In a fully turgid cells, the values of DPD,OP and TP will be

Options

A. DPD = 10 atm, OP = 15 atm , TP = 5 atm
B. DPD = 5 atm, OP = 12 atm , TP = 7 atm
C. DPD = 2 atm, OP = 7 atm , TP = 5 atm
D. DPD = 0 atm, OP = 15 atm , TP = 15 atm

Answer

To solve the question regarding the values of DPD (Diffusion Pressure Deficit), OP (Osmotic Pressure), and TP (Turgor Pressure) in a fully turgid cell, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Turgidity**:
- A fully turgid cell is one that is filled with water to its maximum capacity. In this state, the cell's vacuole is full, exerting pressure against the cell wall.

2. **Defining the Terms**:
- **DPD (Diffusion Pressure Deficit)**: This is the difference between the osmotic pressure of the solution and the turgor pressure of the cell. It indicates the tendency of water to move into the cell.
- **OP (Osmotic Pressure)**: This is the pressure required to prevent the flow of water into the cell by osmosis. It is a measure of the solute concentration inside the cell.
- **TP (Turgor Pressure)**: This is the pressure exerted by the fluid (water) inside the vacuole against the cell wall.

3. **Analyzing the Fully Turgid State**:
- In a fully turgid cell, there is no net movement of water into or out of the cell. This means that the osmotic pressure (OP) and turgor pressure (TP) are equal because the cell is balanced in terms of water movement.
- Therefore, if we denote the osmotic pressure as OP, then TP will also equal OP.

4. **Calculating DPD**:
- Since DPD is defined as:
\[ DPD = OP - TP \]
- In a fully turgid cell, since OP = TP, we can substitute:
\[ DPD = OP - OP = 0 \]

5. **Final Values**:
- If we assume a hypothetical value for OP and TP (e.g., both are 15 atmospheres), then:
- DPD = 0
- OP = 15 atmospheres
- TP = 15 atmospheres

### Conclusion:
In a fully turgid cell:
- DPD = 0
- OP = 15 atmospheres (or any equal value)
- TP = 15 atmospheres (or any equal value)