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In a cross in Drosophila , the heterozyg...

In a cross in Drosophila , the heterozygous member with grey body `(b^(+))` and long wings `(vg^(+))` was crossed with had the following ratio grey vestigial 24 : grey long 126: black long 26 : black vestigial 124 . What is the frequency of recombinant in the population ?

A

`15.8%`

B

`16.7%`

C

`17.5%`

D

`14.5%`

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The correct Answer is:
To solve the problem, we need to calculate the frequency of recombinant offspring in a cross of Drosophila with the given phenotypic ratios. ### Step-by-Step Solution: 1. **Identify the Parental and Recombinant Phenotypes**: - The parental phenotypes are: - Grey body with long wings (B+ vg+) - Black body with vestigial wings (bb vg) - The recombinant phenotypes are: - Grey body with vestigial wings (B+ vg) - Black body with long wings (bb vg+) 2. **Count the Offspring**: - From the given ratios: - Grey vestigial (recombinant) = 24 - Grey long (parental) = 126 - Black long (recombinant) = 26 - Black vestigial (parental) = 124 3. **Calculate Total Offspring**: - Total offspring = Grey vestigial + Grey long + Black long + Black vestigial - Total = 24 + 126 + 26 + 124 = 300 4. **Calculate the Number of Recombinant Offspring**: - Number of recombinant offspring = Grey vestigial + Black long - Number of recombinants = 24 + 26 = 50 5. **Calculate Recombination Frequency**: - Recombination frequency (RF) = (Number of recombinants / Total offspring) × 100 - RF = (50 / 300) × 100 = 16.67% ### Final Answer: The frequency of recombinant in the population is **16.67%**.
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