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A very small hole in an electric furnace...

A very small hole in an electric furnace is used for heating metals. The hole nearly acts as black body. The area of the hole is `200mm^(2)` To keep a metal at `727^(@)C` heat energy flowing through this hole per sec in joules is `(sigma =5.67 xx 10^(-8)Wm^(-2)K^(-4))` .

A

22.68

B

2.268

C

1.134

D

11.34

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The correct Answer is:
D
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A very small hole in an electric furnace is used for heating metals. The hole nearly acts as black body. The area of the hole is 200mm^(2) To keep a metal at 727^(@)C heat energy flowing throungh this hole per sec in joules is (sigam =5.67 xx 10^(-8)Wm^(-2)K^(-4)) .

The surface area of a black body is 5xx10^(-4) m^(2) and its temperature is 727^@C . Energy radiated by it per minute is (Take sigma =5.67xx10^(-8) "J m"^(-2) s^(-1) K^(-4) )

The power of black body at temperature 200 K is 544 W .Its surface area is (sigma=5.67xx10^(-8)Wm^(-2)K^(-2))

The surface of a black body is at a tempera ture 727^(@)C and its cross section is 1m^(2) Heat radi ated from this surface in one minute in Joules is (Stefan's constant =5.7 xx 10^(-8) W//m^(2)//k^(4)) .

A body which has a surface area 5.00 cm^(2) and a temperature of 727^(@)C radiated 300 j of energy each minute. What is the emissivity of body? Steafan's constant =5.67xx10^(-8) Wm^(-2) K^(-4) .

A cube, which may be regarded as a perfectly black body, radiates heat at the rate of 2770.2 watt when its temperature is 27^(@)C . The volume of the cube is (sigma=5.7xx10^(8)J//m^(2)" s "K^(4))

Calculate the temperature (in K) at which a perfect black body radiates energy at the rate of 5.67W cm^(-2) . Given sigma = 5.67 xx 10^(8)Wm^(-2)K^(-4) .

If the sun's surface radiates heat at 6.3 xx 10^(7) Wm^(-2) . Calculate the temperature of the sun assuming it to be a black body (sigma = 5.7 xx 10^(-8)Wm^(-2)K^(-4))

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